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Lzilioli improvements #7
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8955f7e
make it possible to differentiate between stdout and stderr when debu…
lzilioli c843f6d
use console.error where appropriate
lzilioli 69ccc04
escape spaces in the file path
lzilioli 49a208e
don't insert empty details (in case an error occured)
lzilioli fd47b66
split into two commands
lzilioli ca0e3af
support legacy style links
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I think you need to escape the
\
here...Try maybe something more complete like:
replace(/(\s+)/g, '\\$1')
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The provided code snippet only escapes the first space in a sequence of many. We need to escape each individual space.
returns
"path/to\\ my\\ file\\ has\\ a\\ lot.\\ of\\ spaces"
Whereas the regex replace in the PR escapes each individual space
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Oops, right, this should work:
Your solution in the PR will just replace the spaces with spaces :)
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So maybe we just need the double quotes and no replace then? The code as modified fixed the issue I was seeing. I do see that my string ends up unmodified with the replace, so it seems like double quotes may be all thats needed here